CDMA - Advanced
This time, assume there are 3 senders whom interfere with eachother and
that the interfering transmitted bit signals are additive. The value received at a
receiver, however, is now the sum of the transmitted bits from all senders.
Assume that sender 1 has a CDMA code of (-1, 1, -1, -1, -1, -1, -1, -1), sender 2 has a CDMA code of (1, -1, 1, 1, -1, -1, 1, 1), and sender 3 has a CDMA code of (-1, -1, 1, 1, 1, -1, 1, -1) and their combined output is: (1, 1, -1, -1, -3, -1, -1, 1)
Question List
1. Assuming you are receiver 1, what is the decoded bit? If it can't be done, answer with 'n/a'
2. Assuming you are receiver 2, what is the decoded bit? If it can't be done, answer with 'n/a'
3. Assuming you are receiver 3, what is the decoded bit? If it can't be done, answer with 'n/a'
Solution
1. Because the CDMA codes weren't well chosen, interference will render the receiver unable to decode the original bit
2. Because the CDMA codes weren't well chosen, interference will render the receiver unable to decode the original bit
3. The decoded bit is: -1 for sender 3
That's incorrect
That's correct
The answer was: n/a
The answer was: n/a
The answer was: -1