Computing end-end delay (transmission and propagation delay)
Consider the figure below, with three links, each with the specified transmission rate and link length.
Assume the length of a packet is 16000 bits. The speed of light propagation delay on each link is 3x10^8 m/sec
Round your answer to two decimals after leading zeros
Question List
1. What is the transmission delay of link 1?
2. What is the propogation delay of link 1?
3. What is the total delay of link 1?
4. What is the transmission delay of link 2?
5. What is the propogation delay of link 2?
6. What is the total delay of link 2?
7. What is the transmission delay of link 3?
8. What is the propogation delay of link 3?
9. What is the total delay of link 3?
10. What is the total delay?
Solution
Link 1 transmission delay = L/R = 16000 bits / 10 Mbps = 0.0016 seconds
Link 1 propagation delay = d/s = ()2 Km) * 1000 / 3*10^8 m/sec = 6.67E-6 seconds
Link 1 total delay = d_t + d_p = 0.0016 seconds + 6.67E-6 seconds = 0.0016 seconds
Link 2 transmission delay = L/R = 16000 bits / 1 Mbps = 0.016 seconds
Link 2 propagation delay = d/s = ()1000 Km) * 1000 / 3*10^8 m/sec = 0.0033 seconds
Link 2 total delay = d_t + d_p = 0.016 seconds + 0.0033 seconds = 0.019 seconds
Link 3 transmission delay = L/R = 16000 bits / 10 Mbps = 0.0016 seconds
Link 3 propagation delay = d/s = ()2 Km) * 1000 / 3*10^8 m/sec = 6.67E-6 seconds
Link 3 total delay = d_t + d_p = 0.0016 seconds + 6.67E-6 seconds = 0.0016 seconds
The total delay = d_L1 + d_L2 + d_L3 = 0.0016 seconds + 0.019 seconds + 0.0016 seconds = 0.023 seconds
That's incorrect
That's correct
The answer was: 0.0016
The answer was: 6.67E-6
The answer was: 0.0016
The answer was: 0.016
The answer was: 0.0033
The answer was: 0.019
The answer was: 0.0016
The answer was: 6.67E-6
The answer was: 0.0016
The answer was: 0.023